The eccentricity of an ellipse is a value e∈[0,1)e \in [0, 1). There are many ways to define eccentricity; one way to describe it is that the lower the eccentricity, the more "circular" an ellipse is.

One way to calculate the eccentricity of an ellipse is e=fae = \frac{f}{a}, where ff is the distance from the center to each focus and aa is the length of the semi-major axis. (This is the same aa found in the equation for an ellipse.)

That being said, if EE is an ellipse with center (3,4)(3,4) and eccentricity 22\frac{\sqrt{2}}{2}, and the farthest distance between two points on EE is 44, which of these could be the coordinates of the foci?

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