Practice problem
Using the tables above, evaluate f(g(1))f(g(1))f(g(1)) and g(f(3))g(f(3))g(f(3)).
f(g(1))=1f(g(1))= 1f(g(1))=1
f(g(1))=2f(g(1))= 2f(g(1))=2
f(g(1))=3f(g(1))= 3f(g(1))=3
g(f(3))=1g(f(3))= 1g(f(3))=1
g(f(3))=2g(f(3))= 2g(f(3))=2
g(f(3))=3g(f(3))= 3g(f(3))=3
Type a concept, like “slope” or “photosynthesis”.