What Is Degree N (Nth Order) Taylor Approximation?

Let $f(x) = \frac{1}{1-x}$. We know that $f(\frac{1}{3}) = \frac{3}{2} = 1.5$. So let's test the accuracy of our Taylor approximation with this.

Use the fifth-degree Taylor polynomial of $f$ about $x=0$ to approximate $f(\frac{1}{3})$. What is the difference between this value and the actual value ($1.5$), rounded to the nearest thousandth?