Practice problem
What is the linear approximation of f(x)=sin(x)f(x) = \sin(x)f(x)=sin(x) at x=π6x = \frac{\pi}{6}x=6π?
y=12x+32y = \frac{1}{2} x + \frac{\sqrt{3}}{2}y=21x+23
y=32x+12y = \frac{\sqrt{3}}{2}x + \frac{1}{2}y=23x+21
y=32x+6−π312y = \frac{\sqrt{3}}{2}x + \frac{6 - \pi\sqrt{3}}{12}y=23x+126−π3
y=12x+3−6π12y = \frac{1}{2} x + \frac{\sqrt{3} - 6\pi}{12}y=21x+123−6π
Type a concept, like “slope” or “photosynthesis”.