Practice problem
Using the table above, which are correct?
h(6)=0h(6)=0h(6)=0
h(6)=1h(6)=1h(6)=1
h(6)=5h(6)=5h(6)=5
h(6)=6h(6)=6h(6)=6
If h(t)=0h(t)=0h(t)=0, t=0t=0t=0
If h(t)=0h(t)=0h(t)=0, t=1t=1t=1
If h(t)=0h(t)=0h(t)=0, t=5t=5t=5
If h(t)=0h(t)=0h(t)=0, t=6t=6t=6
h−1(5)=0h^{-1}(5)=0h−1(5)=0
h−1(5)=1h^{-1}(5)=1h−1(5)=1
h−1(5)=5h^{-1}(5)=5h−1(5)=5
h−1(5)=6h^{-1}(5)=6h−1(5)=6
h−1(t)=1h^{-1}(t)=1h−1(t)=1, t=0t=0t=0
h−1(t)=1h^{-1}(t)=1h−1(t)=1, t=1t=1t=1
h−1(t)=1h^{-1}(t)=1h−1(t)=1, t=5t=5t=5
h−1(t)=1h^{-1}(t)=1h−1(t)=1, t=6t=6t=6
Type a concept, like “slope” or “photosynthesis”.
