Practice problem
For f(x)=11x+7f(x)=11x+7f(x)=11x+7, what is f−1(x)f^{-1}(x)f−1(x)?
f−1(x)=x11−7f^{-1}(x)=\frac{x}{11}-7f−1(x)=11x−7
f−1(x)=−x−711f^{-1}(x)=-\frac{x-7}{11}f−1(x)=−11x−7
f−1(x)=x+711f^{-1}(x)=\frac{x+7}{11}f−1(x)=11x+7
f−1(x)=x−711f^{-1}(x)=\frac{x-7}{11}f−1(x)=11x−7
Type a concept, like “slope” or “photosynthesis”.