Practice problem
For f(x)=9+10xf(x)=9+10xf(x)=9+10x, what is f−1(x)f^{-1}(x)f−1(x)?
f−1(x)=−x−910f^{-1}(x)=-\frac{x-9}{10}f−1(x)=−10x−9
f−1(x)=x10−9f^{-1}(x)=\frac{x}{10}-9f−1(x)=10x−9
f−1(x)=x−910f^{-1}(x)=\frac{x-9}{10}f−1(x)=10x−9
f−1(x)=x+910f^{-1}(x)=\frac{x+9}{10}f−1(x)=10x+9
Type a concept, like “slope” or “photosynthesis”.