Practice problem
f(x)=x3f(x)=x^3f(x)=x3 horizontally stretched by a factor of 444 and shifted up 111 is:
f(x)=(14x)3+1f(x)=\begin{pmatrix}\dfrac14x\end{pmatrix}^3+1f(x)=(41x)3+1
True
False
Not enough information
Type a concept, like “slope” or “photosynthesis”.
