Practice problem
If f(x)=x2−7f(x)=x^2-7f(x)=x2−7 and g(x)=ln(x)−3x2ex−x7g(x)=\dfrac{\ln(x)-3^x}{2e^x-x^7}g(x)=2ex−x7ln(x)−3x find (f∘f)(x)(f\circ f)(x)(f∘f)(x).
x4−14x2+42x^4-14x^2+42x4−14x2+42
−7x14+28exx7+32x−28e2x+ln2(x)−2(3xln(x))(x7−2ex)2\frac{-7x^{14}+28e^xx^7+3^{2x}-28e^{2x}+\ln^2(x)-2(3^x\ln(x))}{(x^7-2e^x)^2}(x7−2ex)2−7x14+28exx7+32x−28e2x+ln2(x)−2(3xln(x))
ln(x2−7)2ex2−7−(x2−7)7−3x2−72ex2−7−(x2−7)7\frac{\ln(x^2-7)}{2e^{x^2-7}-(x^2-7)^7}-\frac{3^{x^2-7}}{2e^{x^2-7}-(x^2-7)^7}2ex2−7−(x2−7)7ln(x2−7)−2ex2−7−(x2−7)73x2−7
3x4+7x2−383x^4+7x^2-383x4+7x2−38
Type a concept, like “slope” or “photosynthesis”.
