Practice problem
=== If f(x)=axbf(x)=ax^bf(x)=axb and f−1(x)=(1a)1bx1bf^{-1}(x)=(\frac1a)^{\frac1b}x^{\frac1b}f−1(x)=(a1)b1xb1 where aaa and bbb are nonzero real numbers, then f(x)f−1(x)f(x)f^{-1}(x)f(x)f−1(x) is also a power function.
True
False
Not enough information given.
Type a concept, like “slope” or “photosynthesis”.