Practice problem
What is the equation of the parabola above?
x=−32y2−9y−52x=-\frac32y^2-9y-\frac52x=−23y2−9y−25
x=3y2−5y+112x=3y^2-5y+\frac{11}2x=3y2−5y+211
x=−2y2+3y−73x=-2y^2+3y-\frac73x=−2y2+3y−37
x=−13y2−113y−2x=-\frac13y^2-\frac{11}3y-2x=−31y2−311y−2
Type a concept, like “slope” or “photosynthesis”.
