Take the function f(x)=x2−5x−24x+3f(x)=\frac{x^2-5x-24}{x+3} and solve for the following values to find lim⁡x→−3f(x)\lim\limits_{x\to-3}{f(x)}. −4−3.1−3.01−3.001→−3→?−3←−2.999−2.99−2.9−2?←\\\begin{array}{|c|c|c|} \hline -4&-3.1&-3.01&-3.001&\rightarrow-3\\ \hline &&&&\rightarrow?\\ \hline \end{array} \\\begin{array}{|c|c|c|} \hline -3\leftarrow&-2.999&-2.99&-2.9&-2\\ \hline ?\leftarrow&&&&\\ \hline \end{array}

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