Practice problem
Which of the following functions has a removable discontinuity?
{x2−1x+1x≠13x=1\begin{cases}\frac{x^2-1}{x+1}&x\neq1\\3&x=1\end{cases}{x+1x2−13x=1x=1
{x2−3x+1x≠13x=1\begin{cases}\frac{x^2-3}{x+1}&x\neq1\\3&x=1\end{cases}{x+1x2−33x=1x=1
{x2−1x−1x≠13x=1\begin{cases}\frac{x^2-1}{x-1}&x\neq1\\3&x=1\end{cases}{x−1x2−13x=1x=1
{x2−42xx≠13x=1\begin{cases}\frac{x^2-4}{2x}&x\neq1\\3&x=1\end{cases}{2xx2−43x=1x=1
Type a concept, like “slope” or “photosynthesis”.
