An object is launched at 19.619.6 meters per second (m/s) from a 58.858.8-meter tall platform. The equation for the object's height ss at time tt seconds after launch is s(t)= –4.9t2+19.6t+58.8s(t) = \ –4.9t^2 + 19.6t + 58.8, where ss is in meters. When does the object (in seconds) strike the ground?

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