Practice problem
Let aaa and bbb be real numbers. What is the derivative of y=(lnxa)by=(\ln x^{a})^{b}y=(lnxa)b
ab(lnx)b−1x\dfrac{ab(\ln x)^{b-1}}{x}xab(lnx)b−1
abb(lnx)ba^{b}b(\ln x)^{b}abb(lnx)b
abb(lnx)b−1x\dfrac{a^{b}b(\ln x)^{b-1}}{x}xabb(lnx)b−1
b(lnxa)b−1xa\dfrac{b(\ln x^{a})^{b-1}}{x^{a}}xab(lnxa)b−1
Type a concept, like “slope” or “photosynthesis”.