Practice problem
What are the roots of the quadratic equation 3x2+4x+2=03x^2+4x+2=03x2+4x+2=0? Hint: use the quadratic equation (x=−b±b2−4ac2ax=\frac{-b\pm\sqrt{b^2-4ac}}{2a}x=2a−b±b2−4ac)
−2+2i3\frac{-2+\sqrt{2}i}{3}3−2+2i
−2−2i3\frac{-2-\sqrt{2}i}{3}3−2−2i
−23\frac{-2}{3}3−2
−2-2−2
−43\frac{-4}{3}3−4
−3+5i3\frac{-3+\sqrt{5}i}{3}3−3+5i
−3−53\frac{-3-\sqrt{5}}{3}3−3−5
Type a concept, like “slope” or “photosynthesis”.