Factorization of a^3+b^3+c^3-3abc
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- Stub explanation Let P(a,b,c)P(a,b,c)P(a,b,c) denote the three-variable polynomial a3+b3+c3−3abca^3+b^3+c^3-3abca3+b3+c3−3abc (a homogeneous polynomial with "total" degree equal…
By Victor Wang, Ishwar Karthik
- The factored form of a polynomial in the form of a3+b3+c3−3abca^3 + b^3 + c^3 - 3abca3+b3+c3−3abc is (a+b+c)(a2+b2+c2−ab−bc−ac)(a + b + c)(a^2 + b^2 + c^2 - ab - bc - ac)(a+b+c)…
By Vinitha Ranganeni
- It turns out that the expression a3+b3+c3−3abca^3 + b^3 + c^3 - 3abca3+b3+c3−3abc has the following factorization: a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−bc−ca)a^3 + b^3 + c^3 - 3abc…
By Sujay Kazi
- In the video above by the YouTube channel Kadas Learning it is explained how to factorize a polynomial of the form a3+b3+c3−3abca^3 + b^3 + c^3 - 3abca3+b3+c3−3abc
By Stefan Cuevas
- Determine all functions f:Z→Zf:\mathbb{Z}\to\mathbb{Z}f:Z→Z such that, for every integer aaa, f(a3)=f(a)3f(a^3)=f(a)^3f(a3)=f(a)3 and for every triple a,b,ca,b,ca,b,c of integer…
By Ankan Bhattacharya