Infinite Limits at Infinity
Read this topicExplanations 4
- There are two types of sequences. The first type of sequence is an arithmetic series. Arithmetic sequences are sequences that have a consistent intervals. To find the sum of an …
By Denis Liu, Expii Team
- A sequence is a list of elements, also known as members. If the order of the members of the sequence are switched, then the sequence is not the same. The length of a sequence is…
By Someone Someone
- (Video) Limits at Infinity by PatrickJMT Here's a video by patrickJMT showing you how to find limits of functions as they approach infinity. When we take a limit as it approache…
By Alex Federspiel
- (Video) Infinite Limits by PatrickJMT In a video by patrickJMT he gives a good explanation of infinite limits. Infinite limits are of the form limx→aM(x)N(x)=NonzeroZero\lim_{x…
By Alex Federspiel
Problems 11
- How does the following function behave for large xxx? f(x)=3x3+2x−34x2−3x+1f(x) = \frac{3x^3 + 2x - 3}{4x^2 - 3x + 1}f(x)=4x2−3x+13x3+2x−3
- True or False\text{True or False}True or False === If fff is a function such that limx→∞f(x)=c\lim_{x \to \infty} f(x) = climx→∞f(x)=c for some real number ccc, then limx→∞1f…
- Select all of the following functions that satisfy limx→∞f(x)=∞.\lim_{x \to \infty} f(x) = \infty.x→∞limf(x)=∞.
- What values of aaa make the following statement true? limx→∞ax=∞\lim_{x\to\infty}{ax}=\inftyx→∞limax=∞
- What values of aaa make the following statement true? limx→∞−2ax=∞\lim_{x\to\infty}{-2^{ax}}=\inftyx→∞lim−2ax=∞
- Evaluate limx→∞(x−x)\lim_{x\to\infty}{(x-\sqrt x)}x→∞lim(x−x)
- Evaluate limx→∞4x3+2x4−x+9x2−12x−19+20x3−6x2\lim_{x\to\infty}{\frac{4x^3+2x^4-x+9x^2-1}{2x-19+20x^3-6x^2}}x→∞lim2x−19+20x3−6x24x3+2x4−x+9x2−1
- Evaluate limx→∞(1x2∗7x5+12−4x+6x3−2x2+8x44x−16+x4−3x2+17x3)\lim_{x\to\infty}{\bigg(\frac{1}{x^2}*\frac{7x^5+12-4x+6x^3-2x^2+8x^4}{4x-16+x^4-3x^2+17x^3}\bigg)}x→∞lim(x21∗4x−16…
- Evaluate, limx→−∞x2+8x2+9\lim_{x\rightarrow-\infty}\frac{x^2+8}{\sqrt{x^2+9}}x→−∞limx2+9x2+8
- Evaluate, limx→01x\lim_{x\rightarrow0}\frac1xx→0limx1
- Evaluate, limx→4+3x4−x\lim_{x\rightarrow4^+}\frac{3x}{4-x}x→4+lim4−x3x