Stop, Drop, or Roll
You might have noticed that on a standard die, the sides with 1 and 6 are opposite, the sides with 2 and 5 are opposite, and the sides with 3 and 4 are opposite. This configuration prevents a player from slanting the rolls in his favor.
Now, suppose someone made a die where 1 and 2 are opposite, 3 and 4 are opposite, and 5 and 6 are opposite. How could you roll that die so that the average outcome is more than 3.5 (the average of 1, 2, 3, 4, 5, and 6)?