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Uniformization and quotients
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Donaldson p. 84 Theorem 3: Holomorphic 1-form on compact Riemann surface with no zeros allows us to construct isomorphism (simple case of uniformization...) pulling back to where is identity (invariant differential). Proof is by using universal cover of to study integration of along different paths in ... get an actual map this way, with essentially corresponding to . Of course, in the final general theory this is a consequence of , and for the global holomorphic 1-forms span dimension one space, which must be generated by this invariant differential (once we've constructed it).
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(Global) holomorphic function on compact Riemann surface must be trivial (constant). Allowing meromorphic with one pole of order one allows us to construct isomorphism . In Weierstrass construction for , the next simplest case, note that has a single pole, which is a double pole!
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The first point arose from (for degree 3 or 4 say) with invariant differential . This is related to second perspective, where so take and . By the proof of first point applied to cut out by (construct compact Riemann surface from this affine chart in the standard way, thinking about monodromy to decide how many patches to add at infinity... if we don't do this carefully we won't get a smooth thing; cf. blowup / normalization / resolve singularities story), we see that what Weierstrass has really done is explicitly construct the uniformizing isomorphism .