Okay, so we want to create the circumcenter of a (non-degenerate) triangle ABC.
Well, let's think about this. The circle that goes through A, B, and C has to go through A and B, B and C, and A and C.
So, let's draw in the perpendicular bisector of AB.
Well, now what?
Think for a moment.
Construct another perpendicular bisector!
If one perpendicular bisector contains all of the centers of the circles that go through A and B, and the other contains all of the centers of the circles of B and C, then their intersection should contain the center of the circle that goes through A, B, and C, i.e. the circumcircle!
So, we draw the perpendicular bisector of BC
Now that we have the circumcenter (H), we can draw the circumcircle of ABC.
As you can see, we have successfully constructed the circumcircle (and circumcenter) of triangle ABC!