Construction: Copying an Angle

Before this, knowConstruction: Copying a Segment

Interactive · 2 questions

Suppose that we have an angle ∠A\angle A. We use the construction method to create a copy ∠B\angle B.

We would like to prove that ∠A≅∠B\angle A\cong\angle B. To do so, we will first walk through the construction.

First, we draw a circle Ω1\Omega_1 with center AA and some nonzero radius. Suppose that this circle meets the sides of the angle at points XaX_a and YaY_a. Thus, AXa=AYaAX_a=AY_a.

We draw one ray with BB as an endpoint. Now, we draw a congruent circle Ω2\Omega_2 with center BB. Denote the intersection of the circle and the ray as XbX_b.

Now, we construct a circle Ω3\Omega_3 with center XbX_b and radius XaYaX_aY_a. Denote the intersection of the two circles as YbY_b. Draw the ray BYbBY_b, and the construction is complete.

We claim that ∠XaAYa≅∠XbBYb\angle X_aAY_a\cong\angle X_bBY_b.

How might we prove this?

Choose all correct answers

Read · 1 min

To copy an angle:

  1. Draw 2 intersecting lines, ll and mm. Let BB be their intersection point.

  2. Draw another line, pp, away from ll and mm. Mark a point on pp, YY. YY will be the vertex of the congruent angle you will form.

  3. Draw a circle of any radius with BB as its center so that it marks two points, AA and CC, on lines ll and mm, respectively.

  4. Now draw a congruent circle to the one you just drew with YY as the center. Label the intersection point of pp and ∘Y\circ Y XX.

  5. Draw a circle with center AA and radius ACAC.

  6. Draw a congruent circle to the one you just drew with XX as the center.

  7. Draw a line from YY to the intersection point of ∘Y\circ Y and ∘X\circ X. Label the intersection point ZZ. So, now you have that ∠ABC≅∠XYZ\angle ABC \cong \angle XYZ. Congratulations, you have just constructed congruent angles!

Type a concept, like “slope” or “photosynthesis”.

↑ ↓ to choose · Enter to openSearch explanations and problems