Entropy Change — Overview & Calculation

Before this, knowEntropy — Definition & Overview

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Recall that entropy is dependent on the internal energy of a system.
dS=1TdU+PTdVdS=\frac{1}{T}dU+\frac{P}{T}dV In turn, the internal energy is dependent on heat and work. dU=đQ+đWdU=đQ+đW If we rearrange our first equation, dU=TdS−PdVdU=TdS-PdV we have two equations for internal energy which must be equivalent. Let's break this down, starting with work.

Work done on an object is given by force times distance, so in differential form, đW=Fdℓ=Fdℓ⋅ℓ2ℓ2=Fℓ2dℓ3=PdV\begin{align}đW&=Fd\ell \\ &=Fd\ell \cdot \frac{\ell ^{2}}{\ell ^{2}} \\ &= \frac{F}{\ell ^{2}}d\ell ^{3} \\ &= PdV \end{align} Of course, we are considering how much work our object, or system, does on the surrounding, thus, đW=−PdVđW=-PdV Substituting this into our equation for internal energy, and comparing, dU=đQ−PdVdU=đQ-PdV dU=TdS−PdVdU=TdS-PdV it becomes obvious that heat and entropy are related in the following manner, đQ=TdSđQ=TdS

Applications

Often times chemists want to calculate the entropy change as things heat and cool. Thus, we want to rearrange our equation, dS=đQTΔS=∫T1T2đQT\begin{align} dS&=\frac{đQ}{T} \\ \Delta S&=\int_{T_{1}}^{T_{2}}\frac{đQ}{T} \end{align} But we run in to a bit of an issue. Our integral is describing two different temperature, but our differential is is heat. Luckily, we can use heat capacity to change our differential to temperature. đQ=mCV,PdTđQ=mC_{V,P}dT mm is the mass of our system, and CV,PC_{V,P} is either the constant volume heat capacity or the constant pressure heat capacity. The choice of which to use should be determined on a case by case basis. Plugging this in to our equation, ΔS=∫T1T2mCV,PdTT=mCV,Pln(T1T2)\Delta S=\int_{T_{1}}^{T_{2}}\frac{mC_{V,P}dT}{T}=mC_{V,P}ln(\frac{T_{1}}{T_{2}}) This is how to calculate the entropy change the reversible heating of a single phase system.

When systems undergo a phase change, the entropy is calculated as by dividing the enthalpy change by the temperature. ΔS=ΔHT\Delta S=\frac{\Delta H}{T}
This is because phase changes occur at constant pressure, thus, dH=TdS+VdP=TdS+0=TdsdH=TdS+VdP=TdS+0=Tds dH=TdSdH=TdS

Video

(Video) Entropy Change For Melting Ice, Heating Water, Mixtures

by The Organic Chemistry Tutor

In this video, The Organic Chemistry Tutor demonstrates entropy change calculations. In this section of the video, he illustrates three examples. Each one deals with a temperature or phase change. After watching this video, you'll understand how to calculate entropy changes!

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