Equivalent Equations
Two equations are equivalent if you can manipulate one equation to get the other equation. We must be able to start at either equation and end up at the other.
So, the question is, how does each possible step work? There are four different strategies that you can use to make equivalent equations: addition, subtraction, multiplication, and division.
We'll go through each type of step you can use with specific examples. Then we'll do a longer example at the end that combines multiple steps.
Strategy 1: Addition
We can add any number to both sides of an equation, but the number we add to both sides must be the same. If not, then we no longer have an equation, and any algebra we do after that is pointless.
Example 1: If we have the equation
x−4=2x+7,
we can add 4 to both sides of the equation to get an equivalent equation:
x−4+4=2x+7+4.
Of course, we can simplify both sides of the equation. The constants on the left hand side cancel out:
x=2x+7+4.
We can also add 7+4 together on the right side:
x=2x+11.
Let's move on to our next strategy, the reverse of addition.
Strategy 2: Subtraction
The reverse of addition is subtraction. This means if we want to get rid of a + something on one side of an equation, we should subtract that something from both sides of the equation.
Example 2: Let's say we have the equation
4+2x=6x.
One option is to subtract 2x to both sides. The reason we'd want to do this is because there is a +2x on the left side, so subtracting 2x gets rid of the + term.
4+2x−2x=6x−2x.
As said before, the −2x and the 2x on the left side cancel out:
4=6x−2x.
We can simplify the right-hand side since both terms are x-terms:
4=4x.
Addition and subtraction are a pair of operations we can do. The other pair is multiplication and division.
Strategy 3: Division
If we have a factor in front of a term we want to get rid of, we can divide it away. We will NEVER divide by 0 because we just aren't allowed to.
Example 3: Let's say we have this equation:
12x=24.
Many times, the goal in an equation is to get the x (or other variable) by itself. We can do this by dividing both sides of the equation by 12:
1212x=1224.
We choose to divide by 12 because x was being multiplied by 12, and these two operations cancel out. So:
x=1224
x=12.
Strategy 4: Multiplication
At last, the last operation is multiplication, or as I like to call it, "backwards division." We can get rid of division by multiplying both sides of the equation by a chosen number. We will not multiply by 0 because the equation that results will be 0=0, which is not helpful in any case. 0=0 is always true even if the equation we started with had a variable in it.
Example 4: Maybe we have the equation
217x+4=5.
Equations generally look nicer and are easier to handle if they don't have fractions. How do we handle this? Get rid of the fraction! The fraction involves a division by 2, so we do the opposite. We multiply both sides of the equation by 2 to undo this:
2×217x+4=2×5.
The multiplication and division on the left-hand side cancel:
17x+4=10.
We haven't fully solved the equation for x, but the point was to show how multiplication works.
Now we'll do a longer example where we work in both directions. We show both directions because the steps must be reversible to have two equations that are equivalent.
Combining the 4 Strategies
Our example is to show that the following two equations are equivalent:
6x+3=5
and
2x−17=7.
We assume that 6x+3=5 and use operations to show that 2x−17=7. Then we go backwards. Think of this as combining the tricks of Examples 1, 2, 3, and 4. Watch out for the fraction!
We start with
6x+3=5,
but how do we know which strategy to use? There are a bunch of choices that will actually work, so we'll pick one. Our starting equation has 6x and our "finished" equation has a 2x, so what number could we multiply both sides of the equation by to turn 6x into 2x?
We'll multiply both sides of the equation by 12:
12×6x+12×3=12×5.
The first term on the left-hand side is a 2x:
2x+12×3=12×5.
The other multiplications are just between numbers: 12×3=36 and 12×5=60, so
2x+36=60.
Now what? We have a 2x like we wanted, but the constant terms need some work. The "finished" equation has a −17 on the left side, so we want to make the constant term on the left smaller.
Subtract 53 from both sides of the equation:
2x+36−53=60−53.
Now simplify:
2x−17=7.
Tada! We have the equation we wanted. But this is only half of the battle.
Now we have to go backwards. We assume that
2x−17=7.
This time we want to use addition, subtraction, multiplication, and division to show that
6x+3=5.
However, this time our job is much easier. In the first part of the example we picked steps that could be reversed. Now we just list out those steps in reverse. Our last step in the first part was subtracting 53 from both sides of the equation, so now we do the opposite: add 53 to both sides:
2x−17+53=7+53.
Simplifying by adding terms together gives
2x+36=60.
This was one of our "in-between" steps earlier, which is always a good sign that we're doing things correctly. We also multiplied both sides of the equation by 12 in the first part of the example, so once again we do the reverse: divide by 12:
122x+36=1260.
Lastly, we can simplify this as
6x+3=5.
Now we're done.
Summary
Two equations are equivalent if we can add, subtract, multiply, and divide numbers from one equation to get the other, regardless of which equation we start with. In doing this it is helpful to remember that addition and subtraction are reverse operations, as are multiplication and division.