Gauss's Law Analog for Magnetics: Absence of Monopoles

$\Phi E = \displaystyle\iint \vec{\mathbf{E}} \cdot \mathrm{d}\vec{\mathbf{A}} = \frac {Q}{\epsilon0}$

I have no idea what you're talking about.

"The $0$ means nothingness so there is nothing.

The integral over the entire surface is $0$ for any surface, which means that no monopole (negative or positive can exist), because if it did, then for at least one surface, it would have been nonzero. The flux is therefore $0$ everywhere.