Infinitude of Primes: Special Case 4n−1
We have seen some proofs of infinitude of primes. Another important theorem related to infinitude of primes is Dirichlet's theorem. This states that for two co-prime integers a and n, there are infinitely many k such that ak+n is a prime. And the proof is really hard. But here we discuss some special cases of this theorem which can be proven easily. Mostly using the idea Euclid used in his proof.
Theorem There are infinitely many primes of the form 4k−1.
Proof For the sake of contradiction, assume the primes are p1,…,pn. Consider the number N=4p1⋯pn−1. If we divide this number by 4, we get remainder −1, or 3. Therefore, it must have a prime factor which is of the form 4k−1. Otherwise, if all prime factors are of the form 4k+1, their product will be 4K+1 type too (check it!). Now, notice that, any prime factor p of N is co-prime to all primes of p1,…,pn. Because if p was one of them, p would divide 1, a contradiction! But this gives us a new prime p which is of the form 4k−1.