The Apothem and Radius

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The apothem and radius are terms defined for regular polygons only, but they carry a great deal of importance.

The apothem of a regular polygon is a segment connecting the center of the polygon to a midpoint of one of the sides, and the radius of a regular polygon is a segment connecting the center of the polygon to one of the vertices.

Now, we will derive some important properties concerning the apothem and radius. Denote the apothem as aa, the radius as rr, the side length as ss, the number of sides as nn, the center as OO, and the vertices as A1,A2,...,AnA_1,A_2,...,A_n.

First, familiarize yourself with the following theorems, which are all fairly trivial:

The apothem is perpendicular to the side it meets.

All apothems are congruent.

All radii are congruent.

Now on to the more interesting stuff!

  1. The area of a regular polygon is ans2\frac{ans}{2}, or one half the product of the apothem and perimeter.

Calculating the area of OA1A2OA_1A_2, [OA1A2]=12A1A2⋅OM[OA_1A_2]=\frac{1}{2}A_1A_2\cdot OM [OA1A2]=12as[OA_1A_2]=\frac{1}{2}as To find the total area, just multiply by the number of sides! [A1A2...An]=12ans[A_1A_2...A_n]=\frac{1}{2}ans

  1. The area of a regular polygon is n2r2sin⁡(2πn)\frac{n}{2}r^2\sin(\frac{2\pi}{n}).

Calculating the area of OA1A2OA_1A_2, [OA1A2]=12OA1⋅OA2sin⁡(2πn)[OA_1A_2]=\frac{1}{2}OA_1\cdot OA_2\sin(\frac{2\pi}{n}) [OA1A2]=12r2sin⁡(2πn)[OA_1A_2]=\frac{1}{2}r^2\sin(\frac{2\pi}{n}) Again, to find the total area, just multiply by nn, the number of sides!

For an interesting observation, those well-versed in basic limits will know the following: limn→0sin⁡nn=1lim_{n\to 0}{\frac{\sin n}{n}}=1 Using this limit here, one may see that as nn goes to ∞\infty, the area approaches πr2\pi r^2, which is exactly what we would expect, since the polygon approaches a circle.

  1. The length of the apothem is a=s2tan⁡(π/n)a=\frac{s}{2\tan(\pi/n)}, while the length of the radius is r=s2sin⁡(π/n)r=\frac{s}{2\sin(\pi/n)}.

Draw the triangle OA1MOA_1M. This is a right triangle, so one may use the basic definitions of the trigonometric ratios to quickly derive the equations above.

Note that a=rcos⁡(πn)a=r\cos(\frac{\pi}{n}), which means that a<ra<r, but that aa and rr get closer as nn increases.

While we are on the topic of lengths, note that by the Pythagorean Theorem: (s2)2+a2=r2\left(\frac{s}{2}\right)^2+a^2=r^2

As a last note, we may use the apothem or radius to find the area purely in terms of the side length, ss, and the number of sides, nn: [A1A2...An]=12ans[A_1A_2...A_n]=\frac{1}{2}ans [A1A2...An]=12s2tan⁡(π/n)ns[A_1A_2...A_n]=\frac{1}{2}\frac{s}{2\tan(\pi/n)}ns [A1A2...An]=ns24tan⁡(π/n)[A_1A_2...A_n]=\frac{ns^2}{4\tan(\pi/n)}

This is more than enough knowledge concerning the apothem and perimeter. Good luck!

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