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Illustrated · 2 min

One way we can solve trigonometric functions is to plug in the equation into a calculator, but oftentimes, it's easier to use the unit circle!

The unit circle

By Gustavb via Wikimedia Commons

But before we dive into how to use the unit circle, let's first talk about trigonometric equations. A trigonometric equation is an equation where there are trig values within the equation. For example,

x+cos(x)=3.5x + cos(x) = 3.5

We could solve for xx, but we need to be mindful of the cosine. A lot of the same techniques you used previously when solving algebraic equations, you will use here, including combining like terms and PEMDAS. That part is pretty straightforward, but the more complicated part comes in when trying to get rid of the cosine! Here is where we can use the unit circle.

Here are some tips for solving trigonometric equations:

Example

We want to solve the following equation for θ\theta in radians.

2cos⁡θsin⁡θ=cos⁡θ2\cos \theta \sin \theta = \cos \theta

Our first step should be to move all terms to the same side, so we can rewrite the equation as:

2cos⁡θsin⁡θ−cos⁡θ=02\cos \theta \sin \theta - \cos \theta= 0

You may notice that each of the two terms has cos⁡θ\cos \theta in it, so we can factor that out from both terms.

cos⁡θ(2sin⁡θ−1)=0\cos \theta(2 \sin \theta - 1)= 0

The zero-product property tells us that at least one of the terms has to equal zero, so we can set them both equal to zero to solve for θ\theta. Let's start with cos⁡θ=0\cos \theta = 0. Going back to our unit circle, we are looking for the radian angle where the xx coordinate is zero. We can see that that angles are π2\frac{\pi}{2} and 3π2\frac{3\pi}{2}. For our second factor, we can say that 2sin⁡θ−1=02 \sin \theta - 1 =0.

2sin⁡θ−1=02sin⁡θ=1sin⁡θ=12\begin{align} 2 \sin \theta - 1 &= 0 \\ 2 \sin \theta &= 1 \\ \sin \theta &= \frac12 \\ \end{align}

On our unit circle, we are looking for the angle where the yy-coordinate is 12\frac12, and that is at the radian angles of π6\frac{\pi}{6} and 5π6\frac{5\pi}{6}.

Looking Further

In the next lesson, you will learn about trig inverses. Once you have mastered that, you will tackle using inverses to solve trig equations. You'll end this section with trig identities and trig word problems.

Video

(Video) Solve Trig Equations with the Unit Circle

by The How and Why of Mathematics

In this video by The How and Why of Mathematics, you will learn about how to find exact solutions to trig equations using the unit circle.

Illustrated · 1 min

The Unit Circle for Trigonometric Equations

We can use the unit circle to solve trigonometric equations. But first, let's review the unit circle.

Unit Circle: Trig Eq.
Quadrant I: all ratios = positive
Quadrant II: sine ratio = positive
Quadrant III: tangent ratio = positive
Quadrant IV: cosine ratio = positive

Image source: By Anusha Rahman

The unit circle can help us to solve trigonometric equations because it easily outlines the major trigonometric ratios. The unit circle is one unit long in its radius, and we essentially build triangles to find the missing part of the ratio.

One important concept to note is that all ratios in Quadrant I will be positive. All sine ratios in Quadrant II will be positive. All tangent ratios in Quadrant III will be positive. Lastly, all cosine ratios in Quadrant IV will be positive.

Type a concept, like “slope” or “photosynthesis”.

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