Practice problem
Find the point(s) of intersection of the circle x2+y2=40x^2 +y^2 =40x2+y2=40 and the line y=2xy=2xy=2x.
(22,42)(2 \sqrt{2}, 4 \sqrt{2})(22,42)
(−22,−42)(-2 \sqrt{2}, -4 \sqrt{2})(−22,−42)
(−22,−22)(-2 \sqrt{2}, -2 \sqrt{2})(−22,−22)
(−42,22)(-4 \sqrt{2}, 2 \sqrt{2})(−42,22)
Type a concept, like “slope” or “photosynthesis”.
