Aceleração de posição a partir de curvas parametrizadas

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Velocity and acceleration follow the same conceptual framework as in one dimension. For instance, assume that said two dimensions are the x and y axes. Then

vy(t)=ddt(y(t))v_y(t) = \frac{d}{dt}(y(t))

vx(t)=ddt(x(t))v_x(t) = \frac{d}{dt}(x(t))

Similarly, acceleration works in much the same way:

ay(t)=ddt(vy(t))=ddt(ddt(y(t)))a_y(t) = \frac{d}{dt}(v_y(t)) = \frac{d}{dt}\left(\frac{d}{dt}(y(t))\right)

ax(t)=ddt(vx(t))=ddt(ddt(x(t)))a_x(t) = \frac{d}{dt}(v_x(t)) = \frac{d}{dt}\left(\frac{d}{dt}(x(t))\right)

Furthermore, as velocity and acceleration are vectors, the magnitudes of the velocity and acceleration can be found by means of the Pythagorean Theorem:

∣v(t)∣=vx(t)2+vy(t)2|v(t)| = \sqrt{v_x(t)^2 + v_y(t)^2}

∣a(t)∣=ax(t)2+ay(t)2|a(t)| = \sqrt{a_x(t)^2 + a_y(t)^2}

In summary, if you know the position vectors in both dimensions, you can find the velocity and acceleration in both dimensions, as well as the overall magnitude of each.

Type a concept, like “slope” or “photosynthesis”.

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