Interactive · 1 question
Gay-Lussac's Law
What is Gay-Lussac's Law?
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Gay-Lussac’s Law states that a gas's pressure is directly proportional to temperature. We assume a constant volume and a constant number of moles.
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In Gay-Lussac’s Law, as pressure increases or decreases, the temperature also increases or decreases.
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There are a few mathematical representations of Gay-Lussac's Law.
- Gay-Lussac’s Law: .
- Gay-Lussac’s Law also states that , where k is the proportionality constant.
- We can write also write Gay-Lussac's Law as a proportionality: .
Gay-Lussac's Law uses kelvin for temperature units, while the pressure units can be any pressure unit (mm Hg, atm, etc.).
Gay-Lussac's Law Formula Cheat Sheet

Image source: Caroline Monahan
Gay-Lussac's Law Visualization


Image source: Caroline Monahan
Gay-Lussac's Law Practice Problem Walkthrough
A 150mL chamber with a fixed amount of oxygen gas has a pressure of 140 atm and a temperature of 60°C. If the temperature is raised 40°C, what is the new pressure of the chamber?
1) Ensure that the units are correct. For Gay-Lussac's Law, we need to have kelvin for temperature. But we are given celsius. So we must convert those numbers to kelvin!
- 60°C + 273.15 = 333.15 K
Because the problem states that the temperature was raised 40°C, we add 40°C to our original temperature.
- 60°C + 40°C + 273.15 = 373.15 K
2) Identify your variables!
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= 140 atm
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= 333.15 K
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= ?
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= 373.15 K
3) Plug the variables into the equation and solve for .
= 156.81 atm
Now try out a problem!
A scientist has a 140mL chamber with a fixed amount of carbon dioxide gas. The scientist noted the pressure to be 300 atm but forgot to write down the temperature in the chamber. If the new pressure is 550 atm, and the new temperature is 50K, what was the original temperature in the chamber?
Practice problem solution:

