More Causes of Deviations from the Ideal Angles
Size of Central Atom
Do you remember the atomic radius trend? It increases down a group of the periodic table. Why? We are adding energy levels. Each additional level pushes the valence electrons further from the nucleus. How does this affect bonding? The two bonding atoms will be further from each other. So, the bond length also expands. How does this affect the ligands? There will be more space between ligands. The electrostatic repulsion gets reduced! So, a larger central atom causes a decrease in the bond angle. For example, let's consider ammonia (NH3) and arsenic trihydride (AsH3). They are both in group five. But arsenic is further down. So, it's larger. Arsenic trihydride has a bond angle of 91.8 degrees. Ammonia is much larger at 107.3 degrees.
Size of Ligand
The size of the ligand also affects electrostatic repulsion. As ligand size increases, so does the bond angle. Why? Large ligands have more prominent electron clouds. So, there will be more electrostatic repulsion. The bond angle expands to minimize the repulsion. For example, consider trifluoromethane (CHF3), tribromomethane (CHBr3), and triiodomethane (CHI3). The halogen-carbon-halogen bond angles are 108.0, 110.0, and 113.0, respectively. The bond angle increases as we move down the halogen series!
Electronegativity
Unfortunately, size isn't the only factor. We also have to consider electronegativity. The greater an element's electronegativity, the more it will pull electron density. In the VSEPR model, electron lone pairs are the prominent source of electron density. In polar bonds, the more electronegative atom pulls the electron lone pairs. So, the repulsion caused by the lone pairs gets limited. What's the result? Our bond angle decreases.
As a side note, size and electronegativity are often competing factors. But, electronegativity tends to be more prominent. Why? Because the electronegativity recasts the electron cloud. More specifically, it alters the lone pairs. In VSEPR, the lone pairs contribute the most to repulsion. Unfortunately, the trend is not universal. So, on some occasions, size matters more.
Multiple Bonds
When we first learned VSEPR, we assumed double and triple bonds had little impact. Sadly, that's not entirely true. More bonds equal more electron density. Remember, in the VSEPR model, we assume bonded electrons are localized. They get stuck between the atoms. With multiple bonds, that means we have more electrons squeezed into place. So, there is more electron density that repels other groups. A great example of this effect is the organic compound formaldehyde. The IUPAC name is methanal (CH2O). Carbon is the central atom. It's double-bonded to the oxygen and single-bonded to each hydrogen. We would expect a trigonal planar geometry with 120-degree angles. But, the double bond increases the repulsion. So, the hydrogen-carbon-hydrogen bond angle is 118 degrees.
Exception to the Octet Rule: Trigonal Bipyrimidal
Before discussing the exceptions to the octet rule, we should learn some new terms. When the bonding atoms are directly above or below the central atom, we call them axial. The other option is to have the ligands distributed around the center plane of the molecule. We call this position equatorial. Let's consider the trigonal bipyramidal geometry. It has two axial and three equatorial positions. It turns out that lone pairs and electronegative elements favor the equatorial position. Why? Around the center, the bond angle is 120 degrees. In the axial position, the bond angle is 90 degrees. So, the equatorial position minimizes the repulsion.