Проста ознака розбіжності невласного інтеграла

Before this, knowОбчислення невласних інтегралів за означенням

Interactive · 1 question

Improper Integrals with unbounded intervals of integration

Now that you know what an improper integral is, you should learn how to test of these integrals actually converge. If an integral converges, its limits exists and approaches a finite number. One of the easiest ways to check for convergence is to see what happens to the integrand as x→∞x\to\infty. Let f(x)f(x) be Riemann integrable on [a,∞][a,\infty]. Then lim⁡b→∞∫abf(x) dx<∞  ⟹  lim⁡x→∞f(x)=0\lim_{b\to\infty}\int_a^b f(x)\,dx<\infty \implies \lim_{x\to\infty} f(x)=0 Notice that the converse is not necessarily true. Take f(x)=1xf(x)=\frac{1}{x}. Then lim⁡x→∞f(x)=0\lim_{x\to\infty} f(x)=0 but the integral does not converge for any a>0a>0: lim⁡b→∞∫ab1x dx=lim⁡b→∞ln⁡(ba)=∞\lim_{b\to\infty}\int_a^b \frac{1}{x}\,dx=\lim_{b\to\infty} \ln\left(\frac{b}{a}\right)=\infty Although the integrand approached zero, the improper integral did not exist.

Remark: There is one caveat here: this test only holds for uniformly continuous functions. For example, see https://en.wikipedia.org/wiki/Fresnel_integral

Which of the following improper integrals could converge?

Choose one answer

Type a concept, like “slope” or “photosynthesis”.

↑ ↓ to choose · Enter to openSearch explanations and problems