Інтуїтивний сенс похідних

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Sensitivity in the Real World

A derivative most essentially measures the "sensitivity" of one quantity to a small change in another quantity. Here are a few examples:

∙\bullet How sensitive is a student's expected exam score to a small change in the amount of time the student spends studying?

∙\bullet How sensitive is the amount of gas purchased at a certain gas station to a small change in the price of gas at that station?

∙\bullet How sensitive is the location of a sprinter to a small change in the time elapsed since the beginning of the race? (You should realize that this basically asks for the velocity of the sprinter, which is why velocity is a derivative.)

These examples help show why derivatives are important; they factor into the student's decision of whether to keep studying and the gas station's decision of whether to raise or lower its price. As the third example shows, derivatives allow us to more precisely say what velocity really is.

Notice that to talk about the sensitivity of one quantity to a small change in another quantity, the first quantity must be a function of the second, that is, the first quantity must depend in a predictable way on the second.

For example, consider the first example above. If we're going to talk about the sensitivity, we need to be able to write the student's expected exam score (say, ss) as a function of the amount of time (say, tt) he/she spends studying. For any value of tt, we should be able to plug it into the function and get a value of ss. That is, there should be a function ff so that s=f(t)s = f(t).

You might notice that the student's expected exam score actually depends on more factors than just the amount of time he/she spends studying--for example, how much sleep the student gets. Does this prevent us from asking about the sensitivity of the student's expected exam score to a small change in the amount of time the student spends studying?

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Video · + 3 min read

(Video) Understanding the Definition of Derivative

by PatrickJMT

Here's a video by patrickJMT explaining derivatives and understanding their definition.

The definition of a derivative is: f′(x)=lim⁡h→0f(x+h)−f(x)hf'(x)=\lim_{h\rightarrow0}\frac{f(x+h)-f(x)}{h}

This probably looks like a jumbled mess of nonsense but we're going to explain everything shortly. First is the notation for a derivative: f′(x)f'(x) and said "f prime of x." The rest of the definition represents the slope of a tangent line at xx.

Say we have a function f(x)f(x), our tangent line at a point is the straight line that extends out from that point.

What we're interested in is finding some way to calculate the slope of this tangent line. We use a roundabout way involving limits to find this. Remember, to find the slope we need two points on the line. We only have one point, which is where the tangent and the function touch.

The point at xx is the only known point.

What we're going to do is find the slope of two points on the graph. So we added some addition points on our function in blue. We want to find the slope of them and our original point in red.

When you take two points on a graph and connect them, the resulting line is called a secant line.

We can find the slope of this secant line because we know two points. But who cares? We're interesting in the slope of our tangent line. The second point of the secant line is far away from our original point. What we're going to do is take a point closer to our original point.

We can find the slope of this closer secant line. But again we want the slope of the tangent line. Well let's make another secant line but with a point even closer.

The idea is as we get closer and closer to our original point, the secant line starts to resemble the tangent line. Since we can find the secant line's slope, we can use this to figure out the tangent line's slope.

So what we're doing is find the slopes of secant lines. Let's label them arbitrarily on our graph. The first secant line we made has a slope of s1s_1, the second s2s_2 and so on.

What we do is pick points closer and closer to xx and find the slopes of those secant lines. The key idea becomes: slope oflimit of thetangent=slopes of thelinesecant lines\begin{array}{ccc} \text{slope of}&&\text{limit of the}\\ \text{tangent}&=&\text{slopes of the}\\ \text{line}&&\text{secant lines} \end{array}

From here we just need to make this key idea mathematical. So let's just go back to when we had one secant line.

To find the slope of secant need to know the other point. Let's say that its some distance hh away from our original point.

So if we're originally sitting at the point xx and we go a distance of hh our new point will be x+hx+h.

Now we can generically label our two points as (x,f(x))(x,f(x)) and (x+h,f(x+h))(x+h,f(x+h)).

So now the slope of the secant line becomes: f(x+h)−f(x)(x+h)−x\frac{f(x+h)-f(x)}{(x+h)-x} We can simplify the denominator by adding the xx and −x-x together: f(x+h)−f(x)h\frac{f(x+h)-f(x)}{h}

Now we want to define the slope of the tangent line by using slopes of secant lines. So we define the tangent slope as f′(x)f'(x). f′(x)=      f(x+h)−f(x)hf'(x)=\ \ \ \ \ \ \frac{f(x+h)-f(x)}{h}

But we're not done yet. We wanted to take the limit of these secant slopes. We also wanted to take the points as they got closer and closer to our original xx value. As the points get closer the distance between them decreases. So our hh value, the distance between the points, gets smaller and smaller. So the limit is as hh approaches 00, which means we take points until there's no distance between them. f′(x)=lim⁡h→0f(x+h)−f(x)hf'(x)=\lim_{h\rightarrow0}\frac{f(x+h)-f(x)}{h} Look at that! We now have a formula that gives us the slope of a tangent line!

Type a concept, like “slope” or “photosynthesis”.

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