Коли дві квадратичні функції співпадають?

Interactive · 10 questions

There are two ways to tell if quadratic functions are identical:

  1. If their equations, y=f(x)y = f(x), are equivalent
  2. If their graphs share 3 points in common

Both of these are pretty straightforward to work with (yay!). We'll look at an example of each below.

Approach 1: Are the equations equivalent?

This will probably require you to mess around with (i.e., rearrange) at least one of the equations to see if you can get it to look like the other.

The equation of a quadratic function in xx will look like y=ax2+bx+cy = ax^2+bx+c: a quadratic equation in two variables. Let's first review how to tell if two quadratic equations in a single variable are equivalent.

So, are these two quadratic equations equivalent?

The bottom one appears to be in its simplest form, so let's see if we can take the top one and rearrange it to look the same.

Now, we need to factor the quadratic expression on the left, x2−2x−8x^2 - 2x - 8.

We can see that, once we simply and factor in the second equation, the quadratic expressions on the left are the same.

Here's another example: are these two equations equivalent?

y=(x−2)(x−3)y = \left(x-2\right)\left(x-3\right) and y=x2−4x+3y = x^2-4x+3

Choose one answer

Read · 1 min

Two quadratic functions are identical if they coincide at 3 distinct points. This is a good, and accurate definition, but without graphing the entire function, how else can we verify this is true?

One method for this is to plug in 3 separate values for x and see if they come up with the same answer. For example, we have two quadratic functions: y1=x2+2x+3,y2=(x−2)2+6x−1y_1=x^2+2x+3, y_2=(x-2)^2+6x-1Let's decide if these are identical or not. We can choose different values for x and see what the functions return. Let's use x=0,x=1,x=2x=0, x=1, x=2. Solving for x=0x=0, either with a calculator or by had gives us y1=3,y2=3y_1=3, y_2=3. That's great, but not enough to prove they are identical. We need 2 more points. This time, when x=1x=1 we get y1=6,y2=6y_1=6, y_2=6. This is looking good. Just one more point will do it. Last, when x=2x=2 we get y1=11,y2=11y_1=11, y_2=11. This is enough to prove the functions are identical.

(As a side note, x=2x=2 was a smart choice for this problem because then the first term in y2y_2 would become zero since (2−2)2=0(2-2)^2=0. Utilize tricks like this whenever possible to make your calculations faster and easier).

Another method to use would be putting both quadratic functions into standard form. For quadratic functions, this form is:y=ax2+bx+cy=ax^2+bx+c Let's use the same functions from the first example, y1y_1 and y2y_2. y1y_1 is already in standard form, so the next step would be to simplify y2y_2 and put it in standard form.y2=(x−2)2+6x−1y_2=(x-2)^2+6x-1y2=x2−4x+4+6x−1y_2=x^2-4x+4+6x-1y2=x2+2x+3y_2=x^2+2x+3Putting y2y_2 into standard form shows us that it is the same as y1y_1.

Read · 1 min

Two quadratic functions are identical if their equations are the same, or if they coincide at three distinct points. This is true because there is at most one quadratic through any three distinct points.

Type a concept, like “slope” or “photosynthesis”.

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