Interactive · 2 questions
Suppose that we have an angle . We use the construction method to create a copy .
We would like to prove that . To do so, we will first walk through the construction.
First, we draw a circle with center and some nonzero radius. Suppose that this circle meets the sides of the angle at points and . Thus, .
We draw one ray with as an endpoint. Now, we draw a congruent circle with center . Denote the intersection of the circle and the ray as .
Now, we construct a circle with center and radius . Denote the intersection of the two circles as . Draw the ray , and the construction is complete.
We claim that .
How might we prove this?
The way to go is triangle congruence!
Now, one more question: which congruence rule should we use?
The SSS congruence is the easiest, since we know quite a lot about side lengths.
Since , and since they are circles, we know the following: Moreover, since the circle has center and radius , By SSS congruence, we know the following: Thus, since corresponding parts of congruent triangles are congruent (CPCTC), we know: Indeed, these are our two angles and , and we have shown that they are congruent.
Thus, the proof is complete, and this is a valid construction for copying an angle.