Interactive · 4 questions
Consider a battery with voltage , a resistor with resistance and a capacitor with capacitance all connected in series.
At any time , let be the charge on one plate of the capacitor and let be the current through the circuit.
Using Kirchhoff's junction rule, or the law of conservation of charge, find a differential equation relating and .
In a small time interval , a current of will flow into one of the capacitor plates. Since no charge can leave the same capacitor plate on the other side, the capacitor plate's charge increases by . So, , or .
Using Kirchhoff's loop rule, find a differential equation relating with .
The voltage across the battery is .
The voltage across the resistor is .
The voltage across the capacitor is .
Solve the above equation to find as a function of .
We can rearrange the equation as , or . Integrating both sides we get , where is some constant.
Therefore, we find , where is also some constant that is easy to find. Of course, if the capacitor is uncharged at , .
Thus, qualitatively the capacitor's charge starts at zero and exponentially approaches the maximum charge . A graphic representation of charge vs. time is shown below:
The quantity is the system's "time constant."
What is the significance of the time constant?
Looking back at the function , we see that is actually the time it takes for the difference between capacitor charge and maximum charge in a charging capacitor to decrease by a factor of .
While there is probably nothing very interesting about this number itself, the time constant is still important because it is constant for any Resistor-Capacitor series system regardless of the applied voltage. It also lets you accurately compare the charging rates of different Resistor-Capacitor systems (i.e. if one system has twice the time constant, it charges half as fast).