Turns out, we can use logs to solve exponential equations!
Let's look at an example.
25x+3=63x−4
We can solve this equation using logs!
We can start by taking the log of each side of the equation:
log(25x+3)=log(63x−4)
Then, we can use log properties to solve:
(5x+3)log(2)=(3x−4)log(6)
Isolate the logarithms on one side of the equation:
3x−45x+3=log(2)log(6)
Solve for log(2)log(6) using a calculator:
log(2)log(6)=2.58
Therefore,
3x−45x+3=2.58
Finally, solve for x:
5x+3=2.58(3x−4)
5x+3=7.74x−10.32
13.32=2.74x
x=4.86