Рівняння Арреніуса

Before this, knowFactors Affecting Reaction Rate — Overview & Examples

Read · 4 min

I love to make flatbread. The texture is a perfect combination of soft and crunchy. Dipping it in spiced olive oil adds exceptional flavors. I typically let my dough rise for about an hour. I've noticed my bread has more volume in the summer than in winter. Why is that?

Reaction rates depend on temperature. In my house, we don't have air conditioning. So, in the summer the kitchen is hot. In the winter, we run the heater, but it's not too hot. Bread rises because yeast microbes catalyze the breakdown of starch. The products are glucose and carbon dioxide. The carbon dioxide gas gets trapped in the dough. So, it expands. The reaction is faster at higher temperatures.

So, temperature increases the reaction rates. But, why? Let's study the factors that cause chemical reactions.

How do Reactions Happen? Collisions.

Right now, you're being hit by molecules constantly. Our air consists of diatomic nitrogen and oxygen. There is a little bit of the noble gas, Argon. All these gases are inert, so they don't react with you. But, in a chemical reaction, the molecules experience ten billion collisions per second.

Molecular collisions are the basis of collision theory. For a chemical reaction to happen, the reactant molecules need to collide. Anything that increases the number of collisions heightens the reaction rate. That's part of the reason that temperature affects it. The phase of matter also affects it. Solids have significantly less movement than liquids and gases. So, reactions between solids are slow.

I said ten billion collisions are happening every second. So, why are some reactions so slow? Every chemical reaction should occur within a second. It turns out the number of collisions isn't the only factor.

How do Reactions Happen? Orientation.

We know that molecules need to collide. But, for the reaction to happen, they need the correct orientation. For example, consider the decomposition reaction 2HI(g)→H2(g)+I2(g)2HI_{(g)} \rightarrow H_{2(g)} + I _{2(g)}. We know from VSEPR theory that hydrogen iodide is a linear molecule. So, we have a few possible collision orientations. An HH could hit another HH. An HH could hit an II. Or, an II could hit another II. The reaction only happens when II hits another II. So, even though we have ten billion collisions a second, only a fraction of them could produce a reaction.

Why did I say, "could produce a reaction"? Because not every correctly oriented collision reacts. There is one more factor we need to consider.

How do Reactions Happen? Energy.

So, we know the molecules have to collide with the proper orientation. But, they also need to have enough energy. Let's think about our hydrogen iodide example. The collision needs enough energy to break the hydrogen-iodine covalent bond.

How does a collision store energy? As kinetic energy! When the molecules collide, the kinetic energy transfers to potential energy. With enough potential energy, the bond breaks. The collision overcame the bond energy. So, the reaction proceeds. We call the energy needed to start a reaction its activation energy. As the bond breaks, the molecule enters a transition state. That's the peak energy on an energy diagram.

Here, we also see another reason why temperature affects chemical reactions. Higher temperatures equal more kinetic energy. With more kinetic energy, the system's potential energy increases. When the potential energy exceeds or equals the activation energy, the reaction occurs. It does not ensue when the potential energy is less.

Arrhenius Equation

In the 1890s, Svante Arrhenius created an equation relating rate laws and temperatures. We creatively call it the Arrhenius equation.

k=A×eEARTk=A\times e^{\frac{E_{A}}{RT}}

  • k is the rate constant.

  • A is a constant that comes from the frequency of correctly oriented collisions. Typically, we look up the A value for our reaction.

  • EAE_{A} is the activation energy. Its units need to match the gas constant.

  • R is the gas constant. Typically, we use 8.314Jmol×K8.314\frac{J}{mol\times K}. So our activation energy will be in joules.

  • T is the kelvin temperature.

Calculating Activation Energy

We can use the Arrhenius equation to find the activation energy.

k=A×eEARTk=A\times e^{\frac{E_{A}}{RT}}

Let's take the natural log of both sides.

ln⁡k=−EART+ln⁡A\ln{k}= -\frac{E_{A}}{RT} + \ln{A}.

Notice, this is a y=mx+by=mx+b style equation. If we plot ln⁡k\ln{k} versus 1T\frac{1}{T} than our slope is EAR\frac{E_{A}}{R}. So, we can use the slope of the Arrhenius plot to calculate activation energy.

Remember, we determine rate constants experimentally. Let's say we know two rate constants at two temperatures.

Let's subtract the natural logs of each rate constant.

lnk2−lnk1=(−EART2+ln⁡A)−(−EART1+ln⁡A)ln{k_{2}}-ln{k_1}=(-\frac{E_{A}}{RT_{2}} + \ln{A}) -(-\frac{E_{A}}{RT_{1}} + \ln{A})

Now we can use the rules of logarithms and simplify.

ln⁡K2k1=EAR×(1T2−1T1)\ln{\frac{K_{2}}{k_{1}}}=\frac{E_{A}}{R}\times (\frac{1}{T_{2}}-\frac{1}{T_{1}}).

So, if we know the rate constants at two different temperatures, we can calculate the activation energy.

Video

(Video) Arrhenius Equation Activation Energy and Rate Constant K Explained

by The Organic Chemistry Tutor

In this video, The Organic Chemistry Tutor explains the Arrhenius Equation. It connects the rate constant, activation energy, and temperature. You can manipulate the equation to solve for each of these factors. In the second half of the video, he derives each equation. This video will help you see the usable forms of the Arrhenius Equation.

Illustrated · 1 min

Arrhenius Equation

K=Ae^(-Ea/RT) (the Arrhenius equation drawn out with the negative sign on Ea highlighted)

K equals the rate constant
A equals the Arrhenius constant (frequency factor, usually a provided value)
Ea equals the Activation energy
R equals the ideal gas constant 8.314 J/mol*K
T equals the temperature in Kelvin

The Arrhenius equation describes how temperature can affect the rate of reaction.

From the equation, we can see how an increase in temperature leads to an increase in the reaction constant (k). We can also see how a lower activation energy (Ea) leads to a faster reaction (higher k).

Remember, the reaction constant (k) is directly related to the reaction rate.

We can also rewrite the equation in its linear form by taking the natural log of both sides:

lnK = (-Ea/R) (1/T) + lnA

If we are given two temperatures, we can rewrite the Arrhenius equation as:

ln(K2/K1) = (Ea/R)(1/T1 - 1/T2)

Image Source: By Trisha

Type a concept, like “slope” or “photosynthesis”.

↑ ↓ to choose · Enter to openSearch explanations and problems