Теорема про спряжений корінь

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Thus far, we have learned about various theorems and tests to help us determine the roots of a polynomial such as the rational roots test, intermediate value theorem, Descartes' rule of signs, and the fundamental theorem of algebra.

##Introduction

The conjugate root theorem states that if a root of a polynomial is a complex number a+bia + bi, then its complex conjugate, a−bia - bi, is also a root.

Given the example polynomial: y=2x2+5x−21y = 2x^2 + 5x -21, after using the quadratic formula, we know its roots are −54±1934-\frac{5}{4} \pm \frac{\sqrt{193}}{4}.

Let's say we were only given the root, −54+1934-\frac{5}{4} + \frac{\sqrt{193}}{4}. Using our new theorem, we know its complex conjugate, −54−1934-\frac{5}{4} - \frac{\sqrt{193}}{4} is also a root.

Try this example problem for practice!

Janice was trying to find the roots of the quadratic equation, f(x)=4x2−3x−6f(x) = 4x^2 -3x-6. To help her out, her friend Ethan mentions that one of the roots is x=3+1058x = \frac{3+\sqrt{105}}{8}. What is the other root?

Choose one answer

Illustrated · 1 min

Conjugate Root Theorem

We've got a nifty theorem that will help with understanding the complex roots of polynomials!

Conjugate Root Theorem: If a root of a polynomial is a complex number, a + bi, then the complex conjugate, a-bi, is also a root.

Image source: by Anusha Rahman

If we know that one of the roots of a polynomial is a+bia+bi, then we can assume that the complex conjugate, a−bia-bi is also a factor. Complex roots must appear in conjugate pairs when writing a polynomial with real coefficients.

Video · + 1 min read

(Video) Conjugate Root Theorem

by Joel Speranza Math

In this video by Joel Speranza Math, you will learn about what the conjugate root theorem is and how to prove it.

Summary

Introduction

Let P(z)P(z) be a polynomial with real coefficients. If a+bia+bi is a root of P(z)P(z), so is a−bia-bi.

For example, if we have the polynomial, P(z)=3x4+5z3−2z2+4z−9P(z) = 3x^4 + 5z^3 - 2z^2 + 4z -9, we can see that all of the coefficients (3,5,2,43, 5, 2, 4) are all real numbers.

To find the root of a polynomial, we set it equal to 00 and solve.

0=3x4+5z3−2z2+4z−90 = 3x^4 + 5z^3 - 2z^2 + 4z -9

After doing some math, we will find that the solution to this polynomial is: z=−0.12−1.14iz=-0.12 - 1.14i.

This Theorem allows us to say that in addition to the above root, its conjugate is also a root for this polynomial! Therefore, our other solution is z=−0.12+1.14iz=-0.12 + 1.14i.

These may not be the only solutions, but if given one conjugate as a solution, you can be absolutely sure that the other conjugate is also a solution.

Proof

To understand how this theorem is true, you can watch the video for a walkthrough proof!

Type a concept, like “slope” or “photosynthesis”.

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